22v^2-48v-54=0

Solution for 22v^2-48v-54=0 equation:

22v^2-48v-54=0

a = 22; b = -48; c = -54;
Δ = b2-4ac
Δ = -482-4·22·(-54)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-84}{2*22}=\frac{-36}{44}
=-9/11
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+84}{2*22}=\frac{132}{44}
=3
$